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Why floating-point addition isn't associative

Schoolroom math says (a + b) + c equals a + (b + c). On a real computer it doesn't, and that one fact ripples out into nondeterministic GPU reductions, irreproducible training runs, and LLM outputs that aren't bit-stable across hardware.

Computer Science intermediate May 2, 2026

Why it exists

You re-run the same training script with the same seed, the same data, the same model, the same hardware. The loss curve at step 10,000 is almost the same as last time — but not quite. Off by 0.0003. Run it again: off by something different. Nothing in your code changed. Nothing in your config changed. The bits going into the GPU are identical. The bits coming out aren’t. This is not a bug in CUDA or in your framework. It’s the consequence of a single, deeply unintuitive fact about computer arithmetic: floating-point addition isn’t associative. (a + b) + c and a + (b + c) can give different answers, and on modern hardware they routinely do.

The reason is finite precision. A real number has, in principle, infinitely many digits. A floating-point number has a fixed number of bits — 32, 16, 8 — split between an exponent (how big) and a mantissa (how precisely). After every single arithmetic operation, the result is rounded back to fit. Round, round, round. Once you accept that, the non-associativity is forced: the rounding intermediate values you produce depends on the order you produced them in. Different order, different intermediates, different rounding errors, different final answer.

This is not a flaw the standards committee forgot to fix. IEEE 754 — the spec almost every CPU and GPU implements — is deliberately non-associative. The trade is intentional: fixed-width floats give you reproducible per-operation rounding in exchange for giving up the algebraic laws of the real numbers. You keep one and lose the other; you can’t have both at finite cost.

Why it matters now

This sounds like a textbook curiosity. It isn’t — it’s the load-bearing explanation for several things engineers hit constantly in 2026.

The short answer

float non-associativity = finite mantissa + rounding after every op

Real numbers carry as many digits as they need. Floating-point numbers don’t — every result gets rounded to a fixed mantissa width. Rounding is where the information loss happens, and information loss isn’t order-invariant. Re-arrange the additions, you re-arrange which intermediate values get rounded, and that changes the final answer. The same equation, evaluated two valid ways, gives two slightly different floats.

How it works

Here is the cleanest counterexample. In FP32, with a = 1e20, b = -1e20, c = 1:

import numpy as np
a, b, c = np.float32(1e20), np.float32(-1e20), np.float32(1.0)
(a + b) + c   # → 1.0
a + (b + c)   # → 0.0

Same three numbers. Same operator. Different parenthesization. Different answer. (You can paste those four lines into a Python shell and reproduce the split.)

Walk through (a + b) + c. First 1e20 + (-1e20) = 0 exactly — two equal- magnitude opposites cancel, no rounding needed. Then 0 + 1 = 1. The 1 survived because it never got near a giant number.

Walk through a + (b + c). First -1e20 + 1. The number -1e20 lives at a magnitude where the gap between consecutive FP32 values is enormous — much bigger than 1. (That gap has a name: ULP.) At 1e20, one ULP in FP32 is roughly 2^43 ≈ 9e12. Adding 1 to -1e20 produces a true result that lies between two representable FP32 values, and rounding picks the nearer one — which is -1e20 itself. The 1 was annihilated by the rounding step. Then 1e20 + (-1e20) = 0. The 1 is gone, never to return.

Re-association is what decided whether the small number survived. Pair it with its near-equal partner first and it lives. Pair it with a giant first and it’s silently rounded away.

The general shape: every floating-point operation is round(true_result). Re-association doesn’t change true_result, but it changes which intermediate gets rounded. If a small number meets a big number first, the small one is silently swallowed. If two big numbers meet first and cancel, the small one survives. The associative law is a property of the exact arithmetic underneath, not of the rounded arithmetic the hardware actually performs.

A few consequences fall out of this:

The honest seam: I’m describing the mechanism — finite mantissa plus per-op rounding plus reordering. The empirical question of how much this matters for a given workload (training a 70B model? doing a 3×3 matmul?) depends on numerical conditioning, precision, and reduction strategy in ways that don’t compress to a single rule. For a deeper treatment, the canonical reference is Goldberg, What Every Computer Scientist Should Know About Floating-Point Arithmetic (1991).

Going deeper